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Answer:
sinA = ± [tex]\sqrt{1-cos^2A}[/tex]
Step-by-step explanation:
Using the Pythagorean identity
sin²A + cos²A = 1 ( subtract cos²A from both sides )
sin²A = 1 - cos²A ( take the square root of both sides )
sinA = ± [tex]\sqrt{1-cos^2A}[/tex]