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Answer:
[tex]a)\ 5.06 * 10\³[/tex]
[tex]b)\ 6.079 * 10^6[/tex]
[tex]c)\ 3\ crore = 30\ million[/tex]
[tex]d)\ 999999[/tex]
[tex]e)\ 10478[/tex]
[tex]f)\ 78[/tex]
[tex]g)\ 2730[/tex]
Step-by-step explanation:
Solving (a): 5060 as a power of 10
We simply move the decimal between 5 and 6. The number of zeros to move backward is 4.
So,
[tex]5 0 6 0 = 5.06 * 10^3[/tex]
Solving (b): 6079000 as a power of 10
We simply move the decimal between 6 and 0. The number of zeros to move backward is 4.
So,
[tex]6079000 = 6.079 * 10^6[/tex]
Solving (c): 3 crore to millions
[tex]1\ crore = 10\ million[/tex]
Multiply by 3
[tex]3\ crore = 30\ million[/tex]
Solving (d): The greatest 6 digits
The greatest unit digit is 9. So, we simply write out 9 in 6 places
[tex]Greatest= 99999[/tex]
Solving (e): The least 5-digit formed from 4,1,8,0,7
To do this, we start the number from the smallest non-zero digit.
The remaining 4 digits will then be in an increasing order
So, we have:
[tex]Least = 10478[/tex]
Solving (f):
[tex]18 - 7 + 9 * \frac{48}{6} - 5[/tex]
Using BODMAS
Evaluate the division, first
[tex]18 - 7 + 9 * 8 - 5[/tex]
Then multiplication
[tex]18 - 7 + 72 - 5[/tex]
Add up the remaining digits
[tex]78[/tex]
Solving (g): This question is not clear.
I will assume the expression is:
[tex]\frac{72}{ 12}* [ \frac{180}{4}*{10 +(15 - \frac{45}{9}*2)}][/tex]
Evaluate all divisions
[tex]6* [ 45*{10 +(15 - 5*2)}][/tex]
Solve the multiplication in brackets
[tex]6* [ 45*{10 +(15 - 10)}][/tex]
Remove the inner bracket
[tex]6* [ 45*{10 +5}][/tex]
Evaluate 45 * 10
[tex]6* [ 450 +5}][/tex]
Remove the bracket
[tex]6* 455[/tex]
Multiply
[tex]2730[/tex]