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Sagot :
Answer:
The standard deviation is of 8.586.
Step-by-step explanation:
For each person, there are only two possible outcomes. Either they have a genetic mutation, or they do not. The probability of a person having the mutation is independent of any other person, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
About 9% of the population has a particular genetic mutation.
This means that [tex]p = 0.09[/tex]
900 people are randomly selected.
This means that [tex]n = 900[/tex]
Find the standard deviation for the number of people with the genetic mutation in such groups of 900.
[tex]\sqrt{V(X)} = \sqrt{900*0.09*0.91} = 8.586[/tex]
The standard deviation is of 8.586.
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