420isaenidn
Answered

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write y=2x^2-12x+16 in vertex form

Sagot :

CoastsideDadidn

Answer:

y = 2[tex](x - 3)^{2}[/tex] - 1

Step-by-step explanation:

y = 2[tex]x^{2}[/tex] - 12x + 16  

y = 2([tex]x^{2}[/tex] - 6x + 8)        ( Factor out 2 )

y + 9= 2([tex]x^{2}[/tex] - 6x + 9) + 8 ( Complete the square [tex](\frac{-b}{2} )^{2}[/tex] ) Add 9 both sides  

y + 9 = 2 [tex](x - 3)^{2}[/tex] + 8      (Subtract 9 each side)  

y = 2 [tex](x - 3) ^{2}[/tex] - 1         ( simplify )

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