Answered

Discover new information and insights with the help of IDNLearn.com. Our community is ready to provide in-depth answers and practical solutions to any questions you may have.

The following data were obtained from 4 people Pre-Test Value Post-test Value 43 42 28 29 31 30 28 25 You may also assume that the sample standard deviation for the four differences is 1.6. What is the correct t-statistic and the degrees of freedom for these data

Sagot :

Fichohidn

Answer:

Test statistic = 1.25

Degree of freedom = 3

Step-by-step explanation:

The following data were obtained from 4 people

Pre-Test Value Post-test Value __ d

43 ________42 _________ 1

28_______ 29 ________ - 1

31 ________30 _________ 1

28 ________ 25 _________ 3

μd = (1 + - 1 + 1 + 3) / 4 = 4 /4 = 1

The mean difference, μd = 1

The standard deviation of difference, Sd = 1.6

The test statistic = μd / (Sd / √n)

Test statistic = 1 / (1.6/2) = 1 / 0.8

Test statistic = 1.25

Degree of freedom, = n - 1 = 4 - 1 = 3

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.