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Sagot :
Answer:
The answer is "102.2 milliseconds".
Explanation:
Given:
Size of file = 15 MiB
The transmission rate of the total link= 49.7 Gbps
User = 7
Time of setup = 84.5 ms
calculation:
[tex]1\ MiB = 2^{20} = 1048576\ bytes\\\\1\ MiB = 2^{20 \times 8}= 8388608\ bits\\\\15\ MiB= 8388608 \times 15 = 125829120\ bits\\\\[/tex]
So,
Total Number of bits [tex]= 125829120 \ bits[/tex]
Now
The transmission rate of the total link= 49.7 Gbps
[tex]1\ Gbps = 1000000000\ bps\\\\49.7 \ Gbps = 49.7 \times 1000000000 =49700000000\ bps\\\\FDM \ \ network[/tex]
[tex]\text{Calculating the transmission rate for 1 time slot:}[/tex]
[tex]=\frac{ 49700000000}{7} \ bits / second\\\\= 7100000000 \ bits / second\\\\ = \frac{49700000000}{(10^{3\times 7})} \ in\ milliseconds\\\\ =7100000 \ bits / millisecond[/tex]
Now,
[tex]\text{Total time taken to transmit 15 MiB of file} = \frac{\text{Total number of bits}}{\text{Transmission rate}}[/tex]
[tex]= \frac{125829120}{7100000}\\\\= 17.72\\\\[/tex]
[tex]\text{Total time = Setup time + Transmission Time}\\\\[/tex]
[tex]= 84.5+ 17.72\\\\= 102.2 \ milliseconds[/tex]
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