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What is the volume of a flask containing 0.199mol of Cl2at a temperature of 313K and a pressure of 1.19atm

Sagot :

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Answer:

43.0 L

Explanation:

Step 1: Given and required data

  • Moles of chlorine gas (n): 0.199 mol
  • Temperature (T): 313 K
  • Pressure (P): 1.19 atm
  • Ideal gas constant (R): 0.0821 atm.L/mol.K

Step 2: Calculate the volume of the flask (V)

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 1.99 mol × (0.0821 atm.L/mol.K) × 313 K / 1.19 atm = 43.0 L

The answer is 4.30 L

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