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g Consider a mass-spring system where the spring constant is 5 N/m and the mass on the spring is 0.5 kg. The mass is moved a distance of -0.9 m from its equilibrium position. How much work is done by the spring

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Answer:

The work done by the spring is 2.025 J

Explanation:

Given;

mass on the spring, m = 0.5 kg

spring constant, k = 5 N/m

extension of the spring, x = 0.9 m

The work done by the spring is calculated as;

[tex]W = \frac{1}{2} kx^2\\\\W = \frac{1}{2} \times 5 \times (0.9)^2\\\\W = 2.025 \ J[/tex]

Therefore, the work done by the spring is 2.025 J

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