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Answer:

Step-by-step explanation:

From the given trapezium, the following can be observed:

           i. trapezium ABCD

           ii. AB || DC

           iii. EF || AB

           iv. EF || DC

Let AD ≅ BC, then:

AD = AE + ED

BC = BF + FC

So that with the condition that;

AE ≅ BF

and

ED ≅ CF

So then;

AE:ED ≅ BF:FC

Which implies that;

[tex]\frac{AE}{ED}[/tex] = [tex]\frac{BF}{FC}[/tex]

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