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How much current flows in the circuit if two resistors of 6 connected in parallel are
supplied with potential difference of 12 volts?​


Sagot :

Answer:

4 A

Explanation:

Firstly we need to calculate the equivalent resistance. Since, two resistors of 6 connected in parallel, so equivalent resistance will be given by,

[tex]\longrightarrow[/tex] 1/R = 1/R1 + 1/R2

[tex]\longrightarrow[/tex] 1/R = (1/6 + 1/6) Ω

[tex]\longrightarrow[/tex] 1/R = (1 + 1)/6 Ω

[tex]\longrightarrow[/tex] 1/R = 2/6 Ω

[tex]\longrightarrow[/tex] R = 6/2 Ω

[tex]\longrightarrow[/tex] R = 3 Ω

We know that,

[tex]\longrightarrow[/tex] V = IR

  • V denotes p.d (12V)
  • I denotes current
  • R denotes resistance (3 Ω)

[tex]\longrightarrow[/tex] 12 = I × 3

[tex]\longrightarrow[/tex] 12 ÷ 3 = I

[tex]\longrightarrow[/tex] 4 Ampere = I

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