Answered

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The surface area of a roof with dimensions of 40 feet long by 28 feet wide is how many times the surface area of a floor where the dimensions are 16 feet long by 7 feet wide?

Sagot :

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Answer:

10 times

Step-by-step explanation:

Multiply 40 by 28

1120

Multiply 16 by 7

112

Divide the two numbers

You get 10

Hope this helps!

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