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Answered

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sat Calc section

I don't think there are questions as difficult as this one, but please help​

Sat Calc SectionI Dont Think There Are Questions As Difficult As This One But Please Help class=

Sagot :

Jessmzhou4idn

Answer: D

Explanation:

Area of triangle = [tex]\frac{1}{2} bh[/tex]

  • b = base length
  • h = height

Area of ΔABC =

  • [tex]\frac{1}{2} CE * AB[/tex]
  • [tex]\frac{1}{2} BD * AC[/tex]

Since it's the same triangle, those two areas should equal each other:

[tex]\frac{1}{2} CE*AB=\frac{1}{2} BD*AC\\\frac{1}{2} *9*8=\frac{1}{2} *7*AC\\\frac{1}{2} *72=\frac{7}{2} AC\\36*2=7AC\\AC=\frac{72}{7} =10\frac{2}{7}[/tex]

I hope this is correct

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