Answer:
[tex]y=\frac{1}{2}x+5[/tex]
Step-by-step explanation:
Hi there!
Slope intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0)
1) Determine the slope (m)
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex] where two points that lie on the line are [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]
Plug the given points (-4,3) and (6,8) into the equation
[tex]m=\frac{8-3}{6-(-4)}\\m=\frac{8-3}{6+4}\\m=\frac{5}{10}\\m=\frac{1}{2}[/tex]
Therefore, the slope of the line is [tex]\frac{1}{2}[/tex]. Plug this into [tex]y=mx+b[/tex] :
[tex]y=\frac{1}{2}x+b[/tex]
2) Determine the y-intercept (b)
[tex]y=\frac{1}{2}x+b[/tex]
Plug in one of the given points and solve for b
[tex]8=\frac{1}{2}(6)+b\\8=3+b[/tex]
Subtract 3 from both sides to isolate b
[tex]8-3=3+b-3\\5=b[/tex]
Therefore, the y-intercept is 5. Plug this back into [tex]y=\frac{1}{2}x+b[/tex]:
[tex]y=\frac{1}{2}x+5[/tex]
I hope this helps!
