Muna191926idn
Answered

Get the most out of your questions with IDNLearn.com's extensive resources. Find in-depth and accurate answers to all your questions from our knowledgeable and dedicated community members.

o Calculate the pH of 500 ml of buffer solution containing .2M of ammonium sulphate and 0.3M ammonium hydroxide which 5 2.1% ionized in dilute solution. (kb of ammonium hydroxide is 1.8×10^-5)
​

Sagot :

Answer is 9

pKb=−logK

b=−log10^-5=5

  • A mixture of ammonium hydroxide and ammonium chloride forms a basic buffer solution.

  • Henderson's equation for the basic buffer solution is as given below-

pOH=pKb+log[acid]*[salt]

Substitute values in the above expression.

pOH=5+log0.1*0.1=5

Hence, the pH of the solution is pH=14−pOH=14−5=9

What do you mean by pH ?

  • potential of hydrogen
  • a measure of the acidity or alkalinity of a solution
  • equal to the common logarithm of the reciprocal of the concentration of hydrogen ions in moles per cubic decimetre of solution.
  • Pure water has a pH of 7,
  • acid solutions have a pH of less than 7,
  • and alkaline solution with a pH greater than 7.

Learn more about pH here

https://brainly.com/question/13557815

#SPJ2

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Thank you for choosing IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more solutions.