IDNLearn.com makes it easy to find accurate answers to your specific questions. Join our interactive Q&A platform to receive prompt and accurate responses from experienced professionals in various fields.

A cylindrical container closed of both end has a radius of 7cm and height of 6cm A.)find the total surface area of the container B.) find the volume of the container

Sagot :

Answer:

Step-by-step explanation:

Surface:

surface area = 2 ends + side

The ends are both a circle and they are identical.

area of a circle = [tex]\pi[/tex][tex]r^{2}[/tex]

then  [tex]\pi[/tex][tex]7^{2}[/tex] = 153.93804 [tex]cm^{2}[/tex]

since there are two ends multiply the above by 2

2*153.93804 =307.87608 [tex]cm^{2}[/tex]

the side is the length * height

length = perimeter of the circle , the perimeter of a circle is also the circumference.   circ = 2[tex]\pi[/tex]r

circ = 2*[tex]\pi[/tex]*7 = 53.407075

surface area of the side = 6* 53.407075=320.44245

add the two surfaces areas together :)

total surface area = 320.44245 + 307.87608 = 628.3185307 [tex]cm^{2}[/tex]

Volume:

volume is the area of the end times the height

volume = circle area * height

volume = 153.93804 * 6

volume = 923.62824 [tex]cm^{3}[/tex]

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. For clear and precise answers, choose IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.