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Sagot :
[tex] cos(A) = \frac{ {b}^{2} + {c}^{2} - {a}^{2} }{2bc} [/tex]
The cos A will be b/c
Cosine function
Cosine function in a triangle is the ratio of the adjacent side to that of the hypotenuse
How to solve this problem?
The steps are as follow:
- Given,
AB = c
BC = a
AC = b
- AB is hypotenous whereas AC is adjacent side to A
- According to formula of cos,
Cos A = Adjacent side to A / Hypoteneous
Cos A = AC / AB
Cos A = b / c
Therefore the value of Cos A in given figure will be b / c
Learn more about Cosine function here:
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