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A cube of aluminum of mass 4kg is immersed totally in kerosene. It was found that 50g of kerosene was displaced, if the density of the kerosene is 13.5kg/m³, calculate the length and density of the aluminum cube​

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The length and density of the aluminum cube​ is 15.46 cm and 1,081.1 kg/m³ respectively

Volume of the aluminum

The volume of the aluminum is equal to the weight of the kerosene displaced.

V = 0.05 kg / 13.5 kg/m³

V = 3.7 x 10⁻³ m³

Density of the aluminum

density = mass/volume

density = 4 kg / 3.7 x 10⁻³ m³

density = 1,081.1 kg/m³

Length of the aluminum

V = L³

L = ∛V

L = ∛(3.7 x 10⁻³)

L = 0.1546 m

L = 15.46 cm

Thus, the length and density of the aluminum cube​ is 15.46 cm and 1,081.1 kg/m³ respectively.

Learn more about density here: https://brainly.com/question/6838128

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