IDNLearn.com provides a collaborative environment for finding and sharing knowledge. Whether your question is simple or complex, our community is here to provide detailed and trustworthy answers quickly and effectively.
vedanta Excel In Opt. Mathematics - Book 9 Find the locus of a point which moves so that
(a) Its distance from (1, 2) and (2, -3) are equal.
A point that is equidistant from two points will travel along the perpendicular bisector of the line that joins them. The gradient of the line between (1,2) and (2,-3) is (-3 - 2)/(2 - 1) = -5 The perpendicular gradient = -1/-5 or 0.2 The midpoint between (1,2) and (2,-3) is ((1+2)/2,(2+-3)/2) = (1.5, -0.5) Substituting into y=mx + c -0.5 = 0.2 x 1.5 + c -0.5 = 0.3 + c c = -0.5 - 0.3 = -0.8 So the locus is the line y = 0.2x - 0.8
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is committed to your satisfaction. Thank you for visiting, and see you next time for more helpful answers.
