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Answer:
[tex] Slope, \ m = \frac {11}{-12} [/tex]
Explanation:
Given the following points;
Points on the x-axis (x1, x2) = (9, -3)
Points on the y-axis (y1, y2) = (-3, 8)
To find the slope of a line parallel to a line;
Mathematically, the slope of a line is given by the formula;
[tex] Slope, \ m = \frac {Change \; in \; y-axis}{Change \; in \; x-axis} [/tex]
[tex] Slope, \ m = \frac {y_{2} - y_{1}}{x_{2} - x_{1}} [/tex]
Substituting into the formula, we have;
[tex] Slope, \ m = \frac {8 - (-3)}{-3 - 9} [/tex]
[tex] Slope, \ m = \frac {8 + 3}{-3 - 9} [/tex]
[tex] Slope, \ m = \frac {11}{-12} [/tex]
Therefore, the slope of the parallel line is -11/12.