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Sagot :
Answer:
392 g
Explanation:
The given concentration tells us that in 100 g of solution, there would be 15.3 g of 2-ethyltoluene.
With that in mind we can calculate how many grams of solution would contain 60.0 g of 2-ethyltoluene:
- Mass of solution * 15.3 / 100 = 60.0 g 2-ethyltoluene
- Mass of solution = 392 g
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