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Rachel is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove to get to the safe zone at 242424 meters per second. After 444 seconds of driving, she was 707070 meters away from the safe zone. Let y represent the distance (in meters) from the safe zone after x seconds.

Complete the equation for the relationship between the distance and number of seconds.

y=

Sagot :

MrRoyalidn

Answer:

[tex]y(t) = 166 - 24t[/tex]

Step-by-step explanation:

Given

[tex]v =24[/tex] --- velocity to safe zone

[tex]t = 4[/tex] --- after safe zone

[tex]d_1 = 70[/tex] --- distance from safe zone

Required

Represent as a function

Calculate distance (d) from the safe zone

[tex]d_2 = velocity * time[/tex]

[tex]d_2 = 24 * 4[/tex]

[tex]d_2 = 96[/tex]

From the question, we understand that she is 70 m from zone.

This implies that her current distance is:

[tex]d = d_1 + d_2[/tex]

[tex]d = 70 + 96[/tex]

[tex]d = 166[/tex]

So, the function is:

[tex]y(t) = d - v * t[/tex]

[tex]y(t) = 166 - 24 * t[/tex]

[tex]y(t) = 166 - 24t[/tex]

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