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Sagot :
Answer:
Following are the solution to the given question:
Explanation:
For question a:
It is prevented that the atmospheric [tex]CO_2[/tex] through dissolving in the solution and make carbonic acid [tex](H_2CO_3)[/tex] which reacts with the [tex]NaOH:[/tex]
[tex]CO_2+ H_20\to H_2CO_3\\\\H_2CO_3 + NaOH \to NaHCO_3 +H_2O\\\\H_2CO_3 + 2 NaOH \to Na_2CO_3 + 2H_2O\\\\[/tex]
For question b:
For this, the [tex]NaOH[/tex] reacts with the dissolved [tex]CO_2[/tex] so, the molarity of the [tex]NaOH[/tex] will be decreased.
For question C:
In this, the Phenolphthalein is pink in the basic solution[tex](high \ pH)[/tex] and colorless throughout the acidic solution[tex](low\ pH)[/tex].
if the solution is exposed from the atmosphere, the [tex]CO_2[/tex] is from the air dissolving in the solution, and making the [tex]H_2CO_3[/tex] that gives the [tex]H^{+}\ ions[/tex]
[tex]\to[/tex] lower pH.
[tex]\to[/tex] colorless phenolphthalein
For question D:
[tex]Ba(OH)_2 + 2 HNO_3 \to Ba(NO_3)_2+ 2H_2O\\\\[/tex]
Calculating the moles of[tex]HNO_3 = volume \times \text{concentration of} HNO_3\\\\[/tex]
[tex]= \frac{25}{1000} \times 0.200\\\\= 0.005\ mol\\\\[/tex]
Calculating the moles of [tex]Ba(OH)_2= \frac{1}{2} \times\text{moles of}\ HNO_3\\\\[/tex]
[tex]=\frac{1}{2} \times 0.005\\\\= 0.0025 \ mol\\\\[/tex]
Calculating the volume of [tex]Ba(OH)_2=\frac{moles}{concentration\ of\ Ba(OH)_2}[/tex]
[tex]=\frac{0.0025}{0.0293}\\\\=0.08532\ L\\\\= 85.32 \ mL\\\\= 85.3\ mL[/tex]
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