Answer:
(- 2, - [tex]\frac{1}{3}[/tex] )
Step-by-step explanation:
Given the 2 equations
2x + 3y + 5 = 0 → (1)
5x - 3y + 9 = 0 → (2)
Rearrange (1) expressing 3y in terms of x by subtracting 2x + 5 from both sides
3y = - 2x - 5
Substitute 3y = - 2x - 5 into (2)
5x - (- 2x - 5) + 9 = 0 ← distribute parenthesis on left side and simplify
5x + 2x + 5 + 9 = 0
7x + 14 = 0 ( subtract 14 from both sides )
7x = - 14 ( divide both sides by 7 )
x = - 2
Substitute x = - 2 into either of the 2 equations and solve for y
Substituting into (1)
2(- 2) + 3y + 5 = 0
- 4 + 3y + 5 = 0
1 + 3y = 0 ( subtract 1 from both sides )
3y = - 1 ( divide both sides by 3 )
y = - [tex]\frac{1}{3}[/tex]
solution is (- 2, - [tex]\frac{1}{3}[/tex] )
