Answered

Get the most out of your questions with the extensive resources available on IDNLearn.com. Our experts provide prompt and accurate answers to help you make informed decisions on any topic.

Fe-54 = 5.845%
Fe-56 = 91.754%
Fe-58 = 2.119%

(Please help)
Calculate the average atomic mass/ given their percent abundance

Sagot :

Samueladesida43idn

Answer:

55.768

Explanation:

The following information is given in this question:

Fe-54 = 5.845%

Fe-56 = 91.754%

Fe-58 = 2.119%

First, we convert from percentage abundance to decimal abundance

Fe-54 = 5.845% = 0.05845

Fe-56 = 91.754% = 0.91754

Fe-58 = 2.119% = 0.02119

To find the average atomic mass of iron (Fe), we multiply each isotopes' decimal abundance by its mass no and find the sum as follows:

Average atomic mass = (0.05845 × 54) + (0.91754 × 56) + (0.02119 × 58)

Average atomic mass = 3.1563 + 51.38224 + 1.22902

Average atomic mass = 55.768

We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Thank you for choosing IDNLearn.com for your queries. We’re committed to providing accurate answers, so visit us again soon.