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In right triangle PQR, m∠Q = 90° and sin R=5/13
What is the value of cos R?
a) 5/13 b)5/12 c) 12/13 d) 12/5

Sagot :

Answer:

C

Step-by-step explanation:

Given

sinR = [tex]\frac{5}{13}[/tex] = [tex]\frac{opposite}{hypotenuse}[/tex]

This is a 5- 12- 13 triangle with legs PQ = 5, QR = 12, hypotenuse PR = 13

cosR = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{QR}{PR}[/tex] = [tex]\frac{12}{13}[/tex]

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