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Consider the line y=7x-8.

Find the equation of the line that is parallel to this line and passes through the point (6, – 4).
Find the equation of the line that is perpendicular to this line and passes through the point (6, - 4).

Sagot :

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Answer:

a). y = 7x - 46      b). y = -1/7x - 22/7

Step-by-step explanation:

a). y = 7x + b

-4 = 7(6) + b

-4 = 42 + b

-46 = b

y = 7x - 46

b). y = -1/7x + b

-4 = -1/7(6) + b

-4 = -6/7 + b

-22/7 = b

y = -1/7x - 22/7

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