IDNLearn.com makes it easy to find answers and share knowledge with others. Our experts are available to provide in-depth and trustworthy answers to any questions you may have.

A bus leaves Riverside for Springfield and averages only 48 mph. Ten minutes later Smith leaves Riverside for Springfield traveling 64 mph in his car. How long before he overtakes the bus?

Sagot :

Answer:

pls give brainliest even if u dont want to. it will make u better person. when u give brainliest it makes u 3 times smarter

Step-by-step explanation:

Smith overtakes the bus at (2/3)×60=40 minutes

What is speed?

A body is said to have speed v if he travels v distance in unit time.

How to solve it?

Suppose that Smith overtakes the bus at a time 't'. Then the distance traveled by bus is 48×t m and that by Smith is 64×(t-1/6).

Smith needs t-1/6 hours to reach the same position that the bus is in.

Since Smith leaves ten minutes later hence it takes t-1/6 hours for him to overtake the bus.

Because 10 minutes is equal to 10/60=1/6 hour.

So,

48×t=64×(t-1/6)

⇒t=2/3

Hence, Smith overtakes the bus at (2/3)×60=40 minutes

Learn more about speed and distance here-

brainly.com/question/12759408

#SPJ2

Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. IDNLearn.com is your reliable source for answers. We appreciate your visit and look forward to assisting you again soon.