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A box contains 3 red balls, 5 white balls, and 10 green balls. If a ball is chosen at random, what is the probability that it is either white OR green?
a. 3/10
b. 5/6
c. 1/2
d. 1/15

Sagot :

Brucenaomi13idn
B)5/6
Solution
3+5+10=18
White or green ball - 5+10=15
N(e)/N(s) - 15/18
3❌5=15
3❌6=18
Therefore the answer is 5/6
ShubhamchouhanvrVTidn

The correct answer is option B which is the probability of either white or green is 5/6.

What is probability?

Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.

Given that:-

  • A box contains 3 red balls, 5 white balls, and 10 green balls. If a ball is chosen at random.

The probability that it is either white or green will be calculated as:-

Total balls are :- 3+5+10=18

White or green ball - 5+10=15

3 x 5=15

3 x 6=18

P = N(e)/N(s) = 15/18

P = N(e)/N(s) = 5 / 6

Therefore the correct answer is option B which is the probability of either white or green is 5/6.

To know more about probability follow

https://brainly.com/question/24756209

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