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solve |5x+30|=10x ......

Solve 5x3010x class=

Sagot :

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Answer:

Option A

Step-by-step explanation:

We need to solve out ,

[tex]\implies |5x + 30| = 10x [/tex]

We can write it as ,

[tex]\implies 5x + 30 = \pm 10x [/tex]

On simplyfing further,

[tex]\implies 5x + 30 = 10x \quad or \quad 5x +30=-10x [/tex]

On solving the above equation , we will get ,

[tex]\implies \boxed{ x = 6,-2}[/tex]

Now we know that the value of modulus is never negative so when we will put x is equal to 2 on the RHS we will get -20 which is not possible . Therefore , the extraneous root is -2 .

Option A is correct .

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