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find the equation of the straight line passing through the point (0,2) which is perpendicular to line y=1/4x+5

Sagot :

Lanuelidn

Answer:

y = -4x + 2

Step-by-step explanation:

Given the following data;

Points (x1, y1) = (0, 2)

Perpendicular line = y = ¼x + 5

To find the equation of the straight line passing;

Mathematically, the equation of a straight line is given by the formula: y = mx + c

Where;

  • m is the slope.
  • x and y are the points
  • c is the intercept.

From the question, we can deduce that the slope (m) of the perpendicular line is ¼.

y = ¼x + 5 = mx + c

Since the points are perpendicular to the equation of line, it must have a slope that is its negative reciprocal because the slopes of perpendicular lines are negative reciprocals of each other.

Therefore, ¼ = -4

Next, we would write the equation of the straight line using the following formula;

y - y1 = m(x - x1)

Substituting into the formula, we have;

y - 2 = -4(x - 0)

y - 2 = -4x - 0

y - 2 = -4x

y = -4x + 2

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