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Which equation represents the line that passes through points (1, –5) and (3, –17)?

Sagot :

Answer:

y = -6x + 1

Step-by-step explanation:

y = mx + b

b = slope = (-5 - (-17))/(1 - 3) = 12/(-2) = -6

y = -6x + b

-5 = -6(1) + b

b = 1

y = -6x + 1

Answer:

[tex]y=-6x+1[/tex]

Step-by-step explanation:

The linear equation with slope m and intercept c is given as follows:

[tex]y=mx+c[/tex]

The formula for slope of line with points [tex](x_{1} ,y_{2} )[/tex] and [tex](x_{2} ,y_{2} )[/tex] can be expressed as,

[tex]m=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]

The line passes the points that are [tex](1,-5)[/tex] and [tex](3,-17)[/tex]

The slope of the line can be obtained as follows:

[tex]m=\frac{-17-(-5)}{(3)-1}[/tex]

[tex]m=\frac{-12}{2}[/tex]

[tex]m=-6[/tex]

The slope of the line is [tex]-6[/tex]

The line passes through the point [tex](3,-17)[/tex]

Substitute 3 for x, - 6 for m and -17 for y in equation [tex]y=mx+c[/tex] to obtain the value of c.

[tex]-17=-6(3)+c[/tex]

[tex]-17=-18+c[/tex]

[tex]-17+18=c[/tex]

[tex]1=c[/tex]

The equation is [tex]y=-6x+1[/tex]

Hence, the equation of the line that passes through the points [tex](1,-5)[/tex] and [tex](3,-17)[/tex] is [tex]y=-6x+1[/tex]