IDNLearn.com: Your one-stop platform for getting reliable answers to any question. Discover prompt and accurate answers from our experts, ensuring you get the information you need quickly.


Solve a triangle with a =5, b =6, and c = 7. Round to the nearest tenth.


Sagot :

Answer:

<A ≈ 45 degrees

<B ≈ 57 degrees

<C ≈ 78 degrees

Step-by-step explanation:

Hi there!

1) Find <C with the law of cosines

Typically, we want to solve for the angle opposite the largest side first.

Law of cosines: [tex]cosC=\frac{a^2+b^2-c^2}{2(a)(b)}[/tex]

Plug in given values

[tex]cosC=\frac{5^2+6^2-7^2}{2(5)(6)}\\cosC=\frac{1}{5}\\C=cos^-^1(\frac{1}{5} )\\C=78[/tex]

Therefore, <C is approximately 78 degrees.

2) Find <B with the law of cosines

[tex]cosB=\frac{a^2+c^2-b^2}{2(a)(c)}[/tex]

Plug in given values

[tex]cosB=\frac{5^2+7^2-6^2}{2(5)(7)}\\cosB=\frac{19}{35}\\B=cos^-^1(\frac{19}{35})\\B=57[/tex]

Therefore, <B is approximately 57 degrees.

3) Find <A

The sum of the interior angles of a triangle is 180 degrees. To solve for <A, subtract <B and <C from 180:

180-57-78

= 45

Therefore, <A is 45 degrees.

I hope this helps!

We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. Accurate answers are just a click away at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.