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Sagot :
Answer:
See Explanation
Step-by-step explanation:
Given
Let
[tex]S \to[/tex] Strawberry
[tex]B \to[/tex] Banana
[tex]S : B = 2 : 3[/tex]
Solving (a):
Complete the table
The table, to be complete, is not given; so, I will generate one myself.
[tex]\begin{array}{cccccc}S & {2} & {3} & {4} & {5} & {6} \ \\ {B} & {3} & {4.5} & {6} & {7.5} & {9} \ \end{array}[/tex]
The table is generated as follows:
[tex]S : B = 2 : 3[/tex]
Multiply by 1.5
[tex]S : B = 2 * 1.5 : 3 * 1.5[/tex]
[tex]S : B = 3 : 4.5[/tex]
Multiply by 2
[tex]S : B = 2*2 : 3*2[/tex]
[tex]S : B = 4 : 6[/tex]
And so on....
In summary, whatever factor is multiplied to S must be multiplied to B; in order to keep the ratio constant
Solving (b): Why the amount are proportion
Because the ratio is constant and it remains unchanged all through.
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