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Solve for x. Round to the nearest tenth of a degree, if necessary.

Solve For X Round To The Nearest Tenth Of A Degree If Necessary class=

Sagot :

Answer:

x ≈ 60.6°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{IJ}{HI}[/tex] = [tex]\frac{3.9}{2.2}[/tex] , then

x = [tex]tan^{-1}[/tex] ([tex]\frac{3.9}{2.2}[/tex] ) ≈ 60.6° ( to the nearest tenth )

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