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Two ships P and Q left port at the same time. Q sailed at a bearing of 150 degrees while P sailed on the north side of Q. After a distance of 8km and 10km by P and Q respectively, their distance apart is 12km. Find the bearing of P from R​

Sagot :

Samuelthankgodidn

Answer:

247.18

Step-by-step explanation:

please watch the diagram carefully to see marked areas

View image Samuelthankgod
View image Samuelthankgod
View image Samuelthankgod

According to given situation cosine law in trigonometry identities used

[tex]c^{2}=b^{2} +a^{2} -2abcosx[/tex] to find the bearing angle of P from R is 67 degree.

What is trigonometry identities.

If the identities or equations are applicable for all the triangles and not just for right triangles, then they are the triangle identities. These identities will include:

Sine law

Cosine law

Tangent law

According to question,

The angle between RP & RQ.

Using the cosine law

[tex]PQ^{2} = RP^{2} + QR^{2} - 2PR*RQ*cosx\\12^{2}=8^2+10^2-2*8*10cosx\\cosx = \frac{164-144}{160} \\cosx = \frac{20}{160} \\cosx =\frac{1}{8}[/tex]

[tex]x=83[/tex] degree

[tex]150-83=67[/tex]

Hence, the bearing of P from R​ is 67 degree

To know more about cosine law here

https://brainly.com/question/17289163

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