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Suppose that on the average, 7 students enrolled in a small liberal arts college have their automobiles stolen during the semester. What is the probability that less than 1 student will have his automobile stolen during the current semester

Sagot :

Answer:

[tex]P(x>1)=0.9927[/tex]

Step-by-step explanation:

From the question we are told that:

Mean [tex]\=x =7[/tex]

Generally the Poisson equation for \=x is mathematically given by

[tex]P(x>1)=1-P(x \leq 1)[/tex]

Therefor

[tex]P(x>1)=1-(\frac{e^{-7}*7^0}{0!}+{\frac{e^{-7}*7^1}{1!})[/tex]

[tex]P(x>1)=1-(9.1*10^{-4}+6.3*10^{-3})[/tex]

[tex]P(x>1)=1-(7.3*10^{-3}[/tex]

[tex]P(x>1)=0.9927[/tex]