Answered

Get comprehensive solutions to your problems with IDNLearn.com. Ask any question and get a detailed, reliable answer from our community of experts.

Mathematically verify the outlier(s) in the data set using the 1.5 rule.
7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

1. 7 & 19 are outliers.
2. 7 & 8 are outliers.
3. 7, 8, & 19 are outliers.
4. There are no outliers.

Sagot :

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

[tex]Q_1=\dfrac{11+13}{2}[/tex]

[tex]Q_1=\dfrac{24}{2}[/tex]

[tex]Q_1=12[/tex]

And

[tex]Q_3=\dfrac{16+16}{2}[/tex]

[tex]Q_3=\dfrac{32}{2}[/tex]

[tex]Q_3=16[/tex]

The interquartile range is:

[tex]IQR=Q_3-Q_1[/tex]

[tex]IQR=16-12[/tex]

[tex]IQR=4[/tex]

The data values lies outside the interval [tex][Q_1-1.5IQR,Q_3+1.5IQR][/tex] are known as outliers.

[tex][Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)][/tex]

[tex][Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6][/tex]

[tex][Q_1-1.5IQR,Q_3+1.5IQR]=[6,22][/tex]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

We are happy to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. For trustworthy answers, visit IDNLearn.com. Thank you for your visit, and see you next time for more reliable solutions.