Connect with knowledgeable experts and enthusiasts on IDNLearn.com. Our community is here to provide detailed and trustworthy answers to any questions you may have.
Sagot :
Given:
The data values are:
7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19
To find:
The outliers of the given data set.
Solution:
We have,
7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19
Divide the data set in two equal parts.
(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)
Divide each parenthesis in two equal parts.
(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)
Now,
[tex]Q_1=\dfrac{11+13}{2}[/tex]
[tex]Q_1=\dfrac{24}{2}[/tex]
[tex]Q_1=12[/tex]
And
[tex]Q_3=\dfrac{16+16}{2}[/tex]
[tex]Q_3=\dfrac{32}{2}[/tex]
[tex]Q_3=16[/tex]
The interquartile range is:
[tex]IQR=Q_3-Q_1[/tex]
[tex]IQR=16-12[/tex]
[tex]IQR=4[/tex]
The data values lies outside the interval [tex][Q_1-1.5IQR,Q_3+1.5IQR][/tex] are known as outliers.
[tex][Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)][/tex]
[tex][Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6][/tex]
[tex][Q_1-1.5IQR,Q_3+1.5IQR]=[6,22][/tex]
All the data values lie in the interval [6,22]. So, there are no outliers.
Hence, the correct option is 4.
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Find clear and concise answers at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.
