Lm121704idn
Answered

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Solve for x. Round to the nearest tenth of a degree, if necessary.

Solve For X Round To The Nearest Tenth Of A Degree If Necessary class=

Sagot :

Answer:

x ≈ 39.3°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos x = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{KL}{KM}[/tex] = [tex]\frac{6.5}{8.4}[/tex] , then

x = [tex]cos^{-1}[/tex] ([tex]\frac{6.5}{8.4}[/tex] ) ≈ 39.3° ( to the nearest tenth )

Wangjing2312idn

Step-by-step explanation:

Cos theta =Base/hypotenuse

Base=KL= 6.5

Hypotenuse=KM=8.4

Cos X=

[tex] \frac{6.5}{8.4} \\ [/tex]

X=

[tex] {cos}^{ - 1} \frac{6.5}{8.4} [/tex]

X=39.30 (2decimal)

Brainliest please~

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