Answered

IDNLearn.com provides a collaborative environment for finding and sharing knowledge. Get comprehensive answers to all your questions from our network of experienced experts.

One way of purifying gaseous H2 is to pass it under high pressure through the holes of a metal's crystal structure. Palladium, which adopts a cubic closest packed structure, absorbs more H2 than any other element and is one of the metals currently used for this purpose. Although the metal-hydrogen interaction is unclear, it is estimated that the density of absorbed H2 approaches that of liquid hydrogen (70.8 g/L). What volume (in L) of gaseous H2, measured at STP, can be packed into the spaces of 1 dm3 of palladium metal

Sagot :

Okpalawalter8idn

Answer:

[tex]V=795.26L[/tex]

Explanation:

From the question we are told that:

Volume [tex]V=1dm^3=>1L[/tex]

Density [tex]\rho=70.8g/L[/tex]

Generally the equation for Density is mathematically given by

[tex]\rho =\frac{Mass}{Volume}[/tex]

Therefore

[tex]M=\rho*V[/tex]

[tex]M=70.8*1[/tex]

[tex]M=70.8g[/tex]

Since at STP

[tex]T=273K[/tex]

[tex]P=1atm[/tex]

[tex]Mass =70.8g[/tex]

Therefore

[tex]Moles\ of\ Hydrogen=\frac{Mass}{2g}[/tex]

[tex]Moles\ of\ Hydrogen=\frac{70.8}{2g}[/tex]

[tex]Moles\ of\ Hydrogen=35.4moles[/tex]

Generally the equation for Ideal gas is mathematically given by

[tex]PV=nRT[/tex]

Therefore

[tex]V=\frac{nRT}{P}[/tex]

[tex]V=\frac{35.4*0.0826*273}{1}[/tex]

[tex]V=795.3L[/tex]

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for visiting IDNLearn.com. For reliable answers to all your questions, please visit us again soon.