Answered

Join the IDNLearn.com community and start exploring a world of knowledge today. Our Q&A platform is designed to provide quick and accurate answers to any questions you may have.

A chemist makes of nickel(II) chloride working solution by adding distilled water to of a stock solution of nickel(II) chloride in water.Calculate the concentration of the chemist's working solution. Round your answer to significant digits.

Sagot :

Dsdrajlinidn

Answer:

0.0900 mol/L

Explanation:

A chemist makes 330. mL of nickel(II) chloride working solution by adding distilled water to 220. mL of a 0.135 mol/L stock solution of nickel(II) chloride in water. Calculate the concentration of the chemist's working solution. Round your answer to significant digits.

Step 1: Given data

  • Initial concentration (C₁): 0.135 mol/L
  • Initial volume (V₁): 220. mL
  • Final concentration (C₂): ?
  • Final volume (V₂): 330. mL

Step 2: Calculate the concentration of the final solution

We prepare a dilute solution from a concentrated one. We can calculate the concentration of the working solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁/V₂

C₂ = 0.135 mol/L × 220. mL/330. mL = 0.0900 mol/L

Your participation means a lot to us. Keep sharing information and solutions. This community grows thanks to the amazing contributions from members like you. Accurate answers are just a click away at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.