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The slope of diagonal OA is ? and its equation is ?

The Slope Of Diagonal OA Is And Its Equation Is class=

Sagot :

Answer:

Slope = [tex]\frac{4}{3}[/tex]

Equation of the line → [tex]y=\frac{4}{3}x[/tex]

Step-by-step explanation:

Let the equation of diagonal OA is,

y = mx + b

Here, m = Slope of the line OA

b = y-intercept

Slope of a line passing through two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,

m = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Therefore, slope of the line passing through O(0, 0) and A(3, 4) will be,

m = [tex]\frac{4-0}{3-0}[/tex]

m = [tex]\frac{4}{3}[/tex]

Since, line OA is passing through the origin, y-intercept will be 0.

Therefore, equation of OA will be,

[tex]y=\frac{4}{3}x[/tex]

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