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[tex]\displaystyle\ S=Vt=> V=\frac{S}{t }[/tex] in our case, S is d(h) ; and t is t (x), then [tex]\displaystyle\ V=\frac{d(x)}{t(h)}=\bigg(\frac{d}{t} \bigg )(h)=\frac{6h^2-h-1}{2h-1} =\frac{2h^2-h+4h^2-1}{2h-1} =\\\\\\\\\frac{h\underline{(2h-1)}+\underline{(2h-1)}(2h+1)}{2h-1} =\frac{(3h+1)(2h-1)}{2h-1} =\boxed{3h+1}\\\\\\Answer: \boxed{V=3h+1}[/tex]
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