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Find four consecutive integers with the sum of 2021


Sagot :

Answer:

503.75, 504.75, 505.75, 506.75

Step-by-step explanation:

x+(x+1)+(x+2)+(x+3)=2021

4x+6=2021

4x=2015

x=503.75

so it would be

503.75+504.75+505.75+506.75= 2021

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