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It takes 130 j of work to compress a certain spring 0.10m. (a) what is the force constant of this spring? To compress the spring an additional 0.10m, does it take 130

Sagot :

Luv2Teachidn

Answer:

Explanation:

The PE equation for a mass/spring system is

[tex]PE=\frac{1}{2}k[/tex]Δx² and filling in:

[tex]130=\frac{1}{2}k(.10)^2[/tex] and

[tex]k=\frac{2(130)}{(.10)^2}[/tex] so

k = 26000 N/m

If the displacement from equilibrium changes more, the PE needed to compress it will also change.

[tex]PE=\frac{1}{2}(26000)(.20)^2[/tex] gives us that

PE = 520J

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