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A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. The numbers y of cell sites from 1985 through 2014 can be modeled by
y = 340,110/
1 + 377e−0.259t
where t represents the year, with
t = 5 corresponding to 1985.
Use the model to find the numbers of cell sites in the years 1998, 2003, and 2006

Sagot :

MrRoyalidn

Answer:

(a) 74553

(b) 172120

(c) 234802

Step-by-step explanation:

Given

[tex]y = \frac{340110}{1 + 377e^{-0.259t}}[/tex]

Solving (a): 1998

Year 1998 means that:

[tex]t =1998 - 1980[/tex]

[tex]t =18[/tex]

So, we have:

[tex]y = \frac{340110}{1 + 377e^{-0.259*18}}[/tex]

[tex]y = \frac{340110}{1 + 377e^{-4.662}}[/tex]

[tex]y = \frac{340110}{1 + 3.562}[/tex]

[tex]y = \frac{340110}{4.562}[/tex]

[tex]y = 74553[/tex] --- approximated

Solving (b): 2003

Year 2003 means that:

[tex]t = 2003 - 1980[/tex]

[tex]t =23[/tex]

So, we have:

[tex]y = \frac{340110}{1 + 377e^{-0.259*23}}[/tex]

[tex]y = \frac{340110}{1 + 377e^{-5.957}}[/tex]

[tex]y = \frac{340110}{1 + 0.976}[/tex]

[tex]y = \frac{340110}{1.976}[/tex]

[tex]y = 172120[/tex] --- approximated

Solving (c): 2006

Year 2006 means that:

[tex]t = 2006 - 1980[/tex]

[tex]t =26[/tex]

So, we have:

[tex]y = \frac{340110}{1 + 377e^{-0.259*26}}[/tex]

[tex]y = \frac{340110}{1 + 377e^{-6.734}}[/tex]

[tex]y = \frac{340110}{1 + 0.4485}[/tex]

[tex]y = \frac{340110}{1.4485}[/tex]

[tex]y = 234802[/tex] --- approximated

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