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Find the length of side xx in simplest radical form with a rational denominator.

Find The Length Of Side Xx In Simplest Radical Form With A Rational Denominator class=

Sagot :

Answer:

[tex]\frac{5\sqrt{2} }{2}[/tex]

Step-by-step explanation:

Divide 5 by [tex]\sqrt{2}[/tex] , then rationalize denominator

Answer:

Solution given:

Since the given triangle is isosceles and right angled triangle

perpendicular [p]=base[b]=x

hypotenuse [h]=5

we have

by using Pythagoras law

p²+b²=h²

x²+x²=5²

2x²=25

x²=25/2

x²=18

x=[tex]\sqrt{\frac{25}{2}}[/tex]

x=[tex]\bold{\frac{5\sqrt{2}}{2}}[/tex]