Sammyade84idn
Answered

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Write a basic notation for

[tex]a = \frac{(b + d)}{2c} [/tex]
[tex]z = \frac{x}{y + c} [/tex]
[tex] c = \frac{9c + 32}{5} [/tex]





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Sagot :

MrRoyalidn

Answer:

[tex]a = (b + c)/(2 * c)[/tex]

[tex]z = x/(y + c)[/tex]

[tex]c = (9 * c + 32)/5[/tex]

Explanation:

Required

The expression in basic

To do this, we use () to group items, / as divide and * to combine factors

So, we have:

[tex](a)\ a = \frac{(b + d)}{2c}[/tex]

In basic, it is:

[tex]a = (b + c)/(2 * c)[/tex]

[tex](b)\ z = \frac{x}{y + c}[/tex]

In basic, it is:

[tex]z = x/(y + c)[/tex]

[tex](c)\ c = \frac{9c + 32}{5}[/tex]

[tex]c = (9 * c + 32)/5[/tex]

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