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Answer:

Given : A=(1,2)≡(x  

1 ,y  

1

​

) and B=(3,−2)≡(x  

2

​

,y  

2

​

)

Let M=(x,y) be the midpoint of AB

x=(  

2

x  

1

​

+x  

2

​

 

​

) and  y=(  

2

y  

1

​

+y  

2

​

 

​

)

Then, x=  

2

1+3

​

and y=  

2

2−2

​

 

⟹x=2 and y=0

∴M=(2,0)

∴ Coordinates of the midpoint of AB is (2,0)

Step-by-step explanation:

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