Get the information you need from a community of experts on IDNLearn.com. Our experts are available to provide in-depth and trustworthy answers to any questions you may have.
Sagot :
[tex]|1-3x| < 5\\\\x=-1\\\\|1-3\cdot(-1)| < 5\\\\|1+3| < 5\\\\|4| < 5\\\\4 < 5-the\ true[/tex]
[tex]x=1\\\\|1-3\cdot1| < 5\\\\|1-3| < 5\\\\|-2| < 5\\\\2 < 5-the\ true[/tex]
[tex]x=2\\\\|1-3\cdot2| < 5\\\\|1-6| < 5\\\\|-5| < 5\\\\5 < 5-the\ false[/tex]
[tex]|1-3x| < 5\\\\1-3x < 5\ \wedge\ 1-3x > -5\\\\-3x < 5-1\ \wedge\ -3x > -5-1\\\\-3x < 4\ /:(-3)\ \wedge\ -3x > -6\ /:(-3)\\\\x > -\frac{4}{3}\ \wedge\ x < 2\\\\x\in(-\frac{4}{3};\ 2)\\\\I\ x=-1\in(-\frac{4}{3};\ 2)\\\\II\ x=1\in(-\frac{4}{3};\ 2)\\\\III\ x=2\notin(-\frac{4}{3};\ 2)[/tex]
[tex]x=1\\\\|1-3\cdot1| < 5\\\\|1-3| < 5\\\\|-2| < 5\\\\2 < 5-the\ true[/tex]
[tex]x=2\\\\|1-3\cdot2| < 5\\\\|1-6| < 5\\\\|-5| < 5\\\\5 < 5-the\ false[/tex]
[tex]|1-3x| < 5\\\\1-3x < 5\ \wedge\ 1-3x > -5\\\\-3x < 5-1\ \wedge\ -3x > -5-1\\\\-3x < 4\ /:(-3)\ \wedge\ -3x > -6\ /:(-3)\\\\x > -\frac{4}{3}\ \wedge\ x < 2\\\\x\in(-\frac{4}{3};\ 2)\\\\I\ x=-1\in(-\frac{4}{3};\ 2)\\\\II\ x=1\in(-\frac{4}{3};\ 2)\\\\III\ x=2\notin(-\frac{4}{3};\ 2)[/tex]
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Thank you for trusting IDNLearn.com. We’re dedicated to providing accurate answers, so visit us again for more solutions.
