Nutteridn
Answered

Find solutions to your problems with the help of IDNLearn.com's expert community. Get step-by-step guidance for all your technical questions from our dedicated community members.

The perimeter of a rectangle is 30 inches. If it's length is three times it's width, find the dimensions. Show work if possible.

Next, a volleyball coach plans her daily practices to include 10 minutes of stretching, 2/3 of the entire practice scrimmaging, and the remaining practice time working on drills. On Wednesday, the coach planned 100 minutes of stratching and scrimmaging. How long, in hours, is the entire practice? Show work if possible.

Homework due tommorrow......PLEASE HELP!!!!!

Sagot :

Dlesaridn
The rectangle problem:

First, create some variables.
w = width
l = length

Then you know that the length is 3 times the width, so
l = 3w

The equation for perimeter is
P = 2(l+w)

Now you use substitution, substituting the 3w for l because you found that earlier.

P = 2((3w) + w)

And simplify.
P = 2(4w)
P = 8w

And you know P = 30 because they told you that.
30 = 8w
w = 15/4 inches, or 3.75 inches

Now substitute that value back into that first equation,
l = 3w
l = 3(15/4)
l = 45/4 inches, or 11.25 inches.

The dimensions are 11.25in for length and 3.75in for width.

----------------------------------------------------------------------------

The volleyball problem:

100 minutes of stretching and scrimmaging combined, and you know 10 have to be stretching, so 90 is scrimmaging.

s = scrimmaging
T = total time

s = 2/3T   (they gave you this)
90 = 2/3T
T = (90*3)/2
T = 270/2
T = 135 minutes, or 2 hours and 15 minutes.
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. For precise answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.